To determine the similarity between the two triangles, we need to find the measures of the angles in each triangle and see if they correspond.
For triangle ABC:
- \( m\angle A = 47^\circ \)
- \( m\angle B = 36^\circ \)
To find \( m\angle C \): \[ m\angle C = 180^\circ - m\angle A - m\angle B = 180^\circ - 47^\circ - 36^\circ = 97^\circ \]
So, the angles in triangle ABC are:
- \( m\angle A = 47^\circ \)
- \( m\angle B = 36^\circ \)
- \( m\angle C = 97^\circ \)
For triangle GHJ:
- \( m\angle G = 36^\circ \)
- \( m\angle J = 97^\circ \)
To find \( m\angle H \): \[ m\angle H = 180^\circ - m\angle G - m\angle J = 180^\circ - 36^\circ - 97^\circ = 47^\circ \]
The angles in triangle GHJ are:
- \( m\angle G = 36^\circ \)
- \( m\angle H = 47^\circ \)
- \( m\angle J = 97^\circ \)
Next, we can see that the angles in triangles ABC and GHJ are:
- Angles correspond as follows:
- \( m\angle A = 47^\circ \) corresponds to \( m\angle H = 47^\circ \)
- \( m\angle B = 36^\circ \) corresponds to \( m\angle G = 36^\circ \)
- \( m\angle C = 97^\circ \) corresponds to \( m\angle J = 97^\circ \)
Since all corresponding angles are equal, we can conclude that:
\[ \triangle ABC \sim \triangle GHJ \]
Thus, the correct response is:
△ABC∼△GHJ (triangle upper A upper B upper C similar to triangle upper G upper H upper J)