how to solve for radius of horizontal curve with coordinates(NE) for points A,B, C on the curve

Point A : N1405.4018
E1256.7569

Point B : N1283.3703
E1294.7027

Point C : N1225.9373
E1286.6137

3 answers

If a line is horizontal, it is not a curve and the radius is infinity. What are the units of your numbers?

Your question does not make sense to me.
its an arc definition curve with pts A, B, C and have to find the radius of the curve
The center of the circle containing those three points is located where the perpendicular bisectors of AB and BC intersect. Get the equations of the bisectors and solve for their intersection point.
Similar Questions
    1. answers icon 2 answers
    1. answers icon 0 answers
  1. Consider the curve y^2+xy+x^2=15. What is dy/dx?Find the two points on the curve where y equals 0 and show that the tangent
    1. answers icon 0 answers
  2. At what points on the curve y=(x^2)/(2x+5) is the tangent line horizontal?y'=[(2x)(2x+5)-(2)(x^2)]/(2x+5)^2 =[2x^2+10x]/(2x+5)^2
    1. answers icon 1 answer
more similar questions