find the area and perimeter of 9 cm, 8 cm, and 8cm.

1 answer

To find the area and the perimeter of a triangle with side lengths of 9 cm, 8 cm, and 8 cm, we can follow these steps:

Step 1: Determine the Perimeter

The perimeter \( P \) of a triangle is the sum of the lengths of its sides.

\[ P = a + b + c \]

where \( a = 9 , \text{cm} \), \( b = 8 , \text{cm} \), and \( c = 8 , \text{cm} \).

\[ P = 9 + 8 + 8 = 25 , \text{cm} \]

Step 2: Determine the Area

To find the area \( A \), we can use Heron's formula. First, we need to calculate the semi-perimeter \( s \):

\[ s = \frac{P}{2} = \frac{25}{2} = 12.5 , \text{cm} \]

Then, we can use Heron's formula:

\[ A = \sqrt{s(s-a)(s-b)(s-c)} \]

Now, substitute the values:

\[ A = \sqrt{12.5 \times (12.5 - 9) \times (12.5 - 8) \times (12.5 - 8)} \] \[ = \sqrt{12.5 \times 3.5 \times 4.5 \times 4.5} \] \[ = \sqrt{12.5 \times 3.5 \times 20.25} \] \[ = \sqrt{12.5 \times 70.875} \] \[ = \sqrt{886.09375} \] \[ \approx 29.8 , \text{cm}^2 \]

Summary

  • Perimeter: \( 25 , \text{cm} \)
  • Area: \( \approx 29.8 , \text{cm}^2 \)