To determine which ordered pair is part of the solution set for the equation \( y = 4x + 2 \), we can substitute the \( x \)-value from each ordered pair into the equation and see if the resulting \( y \)-value matches the one in the ordered pair.
The equation is \( y = 4x + 2 \).
For each ordered pair:
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(3, 12): \[ y = 4(3) + 2 = 12 + 2 = 14 \quad \text{(not a solution)} \]
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(3, 7): \[ y = 4(3) + 2 = 12 + 2 = 14 \quad \text{(not a solution)} \]
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(3, 45): \[ y = 4(3) + 2 = 12 + 2 = 14 \quad \text{(not a solution)} \]
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(3, 14): \[ y = 4(3) + 2 = 12 + 2 = 14 \quad \text{(solution)} \]
The only ordered pair that is part of the solution set for the equation \( y = 4x + 2 \) is (3, 14).