Use the standard deviation to compare the variability of the datasets. Round to the nearest hundredths.

Dataset A: 4, 5, 6, 12, 13

Dataset B: 4, 5, 7, 9, 10

(1 point)
Responses

The standard deviation of Dataset A is 2.28. The standard deviation of Dataset B is 3.74. The standard deviation of Dataset B is larger than that of Dataset A, so Dataset B has more variability.
The standard deviation of Dataset A is 2.28. The standard deviation of Dataset B is 3.74. The standard deviation of Dataset B is larger than that of Dataset A, so Dataset B has more variability.

The standard deviation of Dataset A is 3.64. The standard deviation of Dataset B is 2.28. The standard deviation of Dataset A is larger than that of Dataset B, so Dataset A has more variability.
The standard deviation of Dataset A is 3.64. The standard deviation of Dataset B is 2.28. The standard deviation of Dataset A is larger than that of Dataset B, so Dataset A has more variability.

The standard deviation of Dataset A is 3.74. The standard deviation of Dataset B is 2.28. The standard deviation of Dataset A is larger than that of Dataset B, so Dataset A has more variability.
The standard deviation of Dataset A is 3.74. The standard deviation of Dataset B is 2.28. The standard deviation of Dataset A is larger than that of Dataset B, so Dataset A has more variability.

The standard deviation of Dataset A is 3.74. The standard deviation of Dataset B is 3.74. Dataset A and Dataset B have the same standard deviation, so both datasets have the same variability.

1 answer

To calculate the standard deviation for both datasets, we can follow these steps:

  1. Calculate the mean (average) of each dataset.
  2. Calculate the squared differences from the mean for each data point.
  3. Calculate the variance by averaging those squared differences.
  4. Take the square root of the variance to get the standard deviation.

Dataset A: 4, 5, 6, 12, 13

  1. Mean = (4 + 5 + 6 + 12 + 13) / 5 = 40 / 5 = 8
  2. Squared differences from the mean:
    • (4 - 8)² = 16
    • (5 - 8)² = 9
    • (6 - 8)² = 4
    • (12 - 8)² = 16
    • (13 - 8)² = 25
  3. Variance = (16 + 9 + 4 + 16 + 25) / 5 = 70 / 5 = 14
  4. Standard deviation = √14 ≈ 3.74

Dataset B: 4, 5, 7, 9, 10

  1. Mean = (4 + 5 + 7 + 9 + 10) / 5 = 35 / 5 = 7
  2. Squared differences from the mean:
    • (4 - 7)² = 9
    • (5 - 7)² = 4
    • (7 - 7)² = 0
    • (9 - 7)² = 4
    • (10 - 7)² = 9
  3. Variance = (9 + 4 + 0 + 4 + 9) / 5 = 26 / 5 = 5.2
  4. Standard deviation = √5.2 ≈ 2.28

Summary of Results

  • The standard deviation of Dataset A is approximately 3.74.
  • The standard deviation of Dataset B is approximately 2.28.

Conclusion

The standard deviation of Dataset A is larger than that of Dataset B, indicating that Dataset A has more variability.

Therefore, the correct response is: The standard deviation of Dataset A is 3.74. The standard deviation of Dataset B is 2.28. The standard deviation of Dataset A is larger than that of Dataset B, so Dataset A has more variability.