To solve the problem, we first need to determine the amount of money Ira has at the end of 6 years after investing in the first account with a 5.6% simple interest rate.
Step 1: Calculate the total amount after 6 years of 5.6% simple interest.
The formula for simple interest is: \[ \text{Total Amount} = \text{Principal} + (\text{Principal} \times \text{Rate} \times \text{Time}) \] Where:
- Principal = $8000
- Rate = 5.6% = 0.056
- Time = 6 years
Calculating the interest earned: \[ \text{Interest} = 8000 \times 0.056 \times 6 = 8000 \times 0.336 = 2688 \]
Now, add the interest to the principal: \[ \text{Total Amount} = 8000 + 2688 = 10688 \]
Step 2: Invest the total amount into a new account at 6% simple interest for 3 years.
Now, Ira invests $10,688 into a new account with a 6% simple interest rate.
Using the same formula for simple interest: \[ \text{Total Amount} = \text{Principal} + (\text{Principal} \times \text{Rate} \times \text{Time}) \] Where:
- Principal = 10688
- Rate = 6% = 0.06
- Time = 3 years
Calculating the interest earned: \[ \text{Interest} = 10688 \times 0.06 \times 3 = 10688 \times 0.18 = 1923.84 \]
Now, add the interest to the principal: \[ \text{Total Amount} = 10688 + 1923.84 = 12611.84 \]
Conclusion
Based on these calculations, we fill in the response areas:
- Ira invests $10,688 into the account that earns 6% simple interest. At the end of 3 years, the account balance is $12,611.84.