Ira invests $8000 into an account that earns 5.6% simple interest for 6 years. He does not make any other deposits or withdrawals.

At the end of 6 years, Ira invests the entire account balance into a different account that earns 6% simple interest. He leaves the money in the account for 3 years without making any additional deposits or withdrawals.

What is the new account balance at the end of 3 years?

Drag and drop values into the boxes to correctly complete the statements.

Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
Ira invests $Response area into the account that earns 6% simple interest. At the end of 3 years, the account balance is $Response area.

483.84, 2688, 10.688, 12,611,84, 13,376

1 answer

To solve the problem, we first need to determine the amount of money Ira has at the end of 6 years after investing in the first account with a 5.6% simple interest rate.

Step 1: Calculate the total amount after 6 years of 5.6% simple interest.

The formula for simple interest is: \[ \text{Total Amount} = \text{Principal} + (\text{Principal} \times \text{Rate} \times \text{Time}) \] Where:

  • Principal = $8000
  • Rate = 5.6% = 0.056
  • Time = 6 years

Calculating the interest earned: \[ \text{Interest} = 8000 \times 0.056 \times 6 = 8000 \times 0.336 = 2688 \]

Now, add the interest to the principal: \[ \text{Total Amount} = 8000 + 2688 = 10688 \]

Step 2: Invest the total amount into a new account at 6% simple interest for 3 years.

Now, Ira invests $10,688 into a new account with a 6% simple interest rate.

Using the same formula for simple interest: \[ \text{Total Amount} = \text{Principal} + (\text{Principal} \times \text{Rate} \times \text{Time}) \] Where:

  • Principal = 10688
  • Rate = 6% = 0.06
  • Time = 3 years

Calculating the interest earned: \[ \text{Interest} = 10688 \times 0.06 \times 3 = 10688 \times 0.18 = 1923.84 \]

Now, add the interest to the principal: \[ \text{Total Amount} = 10688 + 1923.84 = 12611.84 \]

Conclusion

Based on these calculations, we fill in the response areas:

  • Ira invests $10,688 into the account that earns 6% simple interest. At the end of 3 years, the account balance is $12,611.84.