To find out how much Ira has after the 6 years in the first account and then how much he has after investing that total in the second account for 3 years, we can follow these steps:
Step 1: Calculate the account balance after 6 years of 5.6% simple interest.
The formula for simple interest is:
\[
I = P \times r \times t
\]
Where:
\(I\) = Interest earned
\(P\) = Principal amount (initial investment)
\(r\) = Annual interest rate (as a decimal)
\(t\) = Time in years
In this case:
\(P = 8000\)
\(r = 5.6% = 0.056\)
\(t = 6\)
Now we can calculate the interest earned:
\[
I = 8000 \times 0.056 \times 6 = 8000 \times 0.336 = 2688
\]
Now, we add the interest earned to the principal to get the total amount after 6 years:
\[
\text{Total Amount} = P + I = 8000 + 2688 = 10688
\]
Step 2: Calculate the new account balance after investing this amount in the account that earns 6% interest for 3 years.
Now we will use the same simple interest formula for the new investment. Here:
\(P = 10688\) (the total from the first account)
\(r = 6% = 0.06\)
\(t = 3\)
Calculating the interest earned in the new account:
\[
I = 10688 \times 0.06 \times 3 = 10688 \times 0.18 = 1923.84
\]
Now, add the interest earned to the principal to find the total account balance after 3 years:
\[
\text{Total Amount} = P + I = 10688 + 1923.84 = 12611.84
\]
Final Results:
- The amount Ira invests into the account that earns 6% simple interest is $10688.
- At the end of 3 years, the account balance is $12611.84.
Now we can fill in the responses:
Ira invests $10688 into the account that earns 6% simple interest. At the end of 3 years, the account balance is $12611.84.