To analyze the function \( y = 4 \sqrt[3]{\sqrt{x} - 2} \):
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Domain:
- The function involves a square root, \( \sqrt{x} \), which means \( x \) must be non-negative for \( \sqrt{x} \) to be defined. Therefore, the domain is \( x \geq 0 \), which corresponds to the set of all non-negative real numbers.
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Range:
- The expression \( \sqrt{x} - 2 \) can take any real number based on the value of \( x \). Since \( \sqrt{x} \) starts at 0 (when \( x = 0 \)) and increases without bound as \( x \) increases, this means \( \sqrt{x} - 2 \) can go from \( -2 \) to \( +\infty \). When inputted into the cube root function and then multiplied by 4, the output \( y \) can also take all real numbers.
So, the resulting conclusions are:
- The domain of the function is the set of all non-negative real numbers.
- The range of the function is the set of all real numbers.
The correct response is:
The domain of the function is the set of all non-negative real numbers and the range is the set of all real numbers.