To find the equation of the line that passes through the points (6,10) and (18,6), we first need to calculate the slope (m) of the line using the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Where \((x_1, y_1) = (6, 10)\) and \((x_2, y_2) = (18, 6)\).
Plugging in the values:
\[ m = \frac{6 - 10}{18 - 6} = \frac{-4}{12} = -\frac{1}{3} \]
Now that we have the slope, we can use the point-slope form of a line, which is:
\[ y - y_1 = m(x - x_1) \]
Using the point (6, 10) and the slope \(m = -\frac{1}{3}\):
\[ y - 10 = -\frac{1}{3}(x - 6) \]
Now, distribute the slope on the right side:
\[ y - 10 = -\frac{1}{3}x + 2 \]
Next, add 10 to both sides to solve for \(y\):
\[ y = -\frac{1}{3}x + 2 + 10 \] \[ y = -\frac{1}{3}x + 12 \]
The equation of the line in slope-intercept form is:
\[ y = -\frac{1}{3}x + 12 \]
Therefore, the correct response is:
y = −(1/3)x + 12 (which matches the format of some of your options)