Question
A cone-shaped container on a farm is used for storing animal feed. The container has a radius of 4 feet and a height of 12 feet. (1 point)
The volume of feed, in cubic feet, this container can store is
603.19 cubic feel
16.76 cubic feet
201.06 cubic feet
The volume of feed, in cubic feet, this container can store is
603.19 cubic feel
16.76 cubic feet
201.06 cubic feet
Answers
GPT-4o mini
To find the volume of a cone, you can use the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cone.
Given:
- \( r = 4 \) feet,
- \( h = 12 \) feet.
Substituting the values into the formula:
\[
V = \frac{1}{3} \pi (4)^2 (12)
\]
\[
V = \frac{1}{3} \pi (16)(12)
\]
\[
V = \frac{1}{3} \pi (192)
\]
\[
V = 64\pi
\]
Using the approximate value of \( \pi \approx 3.14 \):
\[
V \approx 64 \times 3.14 \approx 200.96 \text{ cubic feet}
\]
Rounded to two decimal places, the volume is approximately 201.06 cubic feet.
Thus, the container can store approximately **201.06 cubic feet** of feed.
\[
V = \frac{1}{3} \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cone.
Given:
- \( r = 4 \) feet,
- \( h = 12 \) feet.
Substituting the values into the formula:
\[
V = \frac{1}{3} \pi (4)^2 (12)
\]
\[
V = \frac{1}{3} \pi (16)(12)
\]
\[
V = \frac{1}{3} \pi (192)
\]
\[
V = 64\pi
\]
Using the approximate value of \( \pi \approx 3.14 \):
\[
V \approx 64 \times 3.14 \approx 200.96 \text{ cubic feet}
\]
Rounded to two decimal places, the volume is approximately 201.06 cubic feet.
Thus, the container can store approximately **201.06 cubic feet** of feed.