Naya planted two fruit trees in her yard. The apple tree is 6 feet tall and will grow at a rate of 5% each year. The cherry tree is 3 feet tall and grows at a rate of 16% each year. How many years will it take the two trees to reach the same height? (1 point) Responses Approximately 2.1 years Approximately 2.1 years Approximately 4.3 years Approximately 4.3 years Approximately 7.0 years Approximately 7.0 years Approximately 8.4 years

1 answer

To find out how many years it will take for the two trees to reach the same height, we can model the height of each tree with the following equations:

For the apple tree: \[ H_a(t) = 6 \times (1 + 0.05)^t = 6 \times (1.05)^t \]

For the cherry tree: \[ H_c(t) = 3 \times (1 + 0.16)^t = 3 \times (1.16)^t \]

We want to find \( t \) such that: \[ H_a(t) = H_c(t) \] This leads to the equation: \[ 6 \times (1.05)^t = 3 \times (1.16)^t \]

Now, we can simplify the equation: \[ 2 \times (1.05)^t = (1.16)^t \]

Divide both sides by \( (1.05)^t \): \[ 2 = \left( \frac{1.16}{1.05} \right)^t \]

Now, take the logarithm of both sides: \[ \log(2) = t \cdot \log\left(\frac{1.16}{1.05}\right) \]

Now we can solve for \( t \): \[ t = \frac{\log(2)}{\log\left(\frac{1.16}{1.05}\right)} \]

Now we calculate the values:

  1. Calculate \( \log(2) \): \[ \log(2) \approx 0.3010 \]

  2. Calculate \( \frac{1.16}{1.05} \): \[ \frac{1.16}{1.05} \approx 1.10476 \]

  3. Then, calculate \( \log(1.10476) \): \[ \log(1.10476) \approx 0.0427 \]

Now, plug these values into the equation for \( t \): \[ t \approx \frac{0.3010}{0.0427} \approx 7.05 \]

So, it will take approximately 7.0 years for the two trees to reach the same height.

Thus, the answer is Approximately 7.0 years.