Let's solve the equation step-by-step using properties of equality, starting from the given equation:
-
Original Equation: \[ 2x + 3y = 6 \]
-
Isolating the \(3y\) term:
Subtract \(2x\) from both sides.
\[ 3y = 6 - 2x \] -
Dividing by 3 to solve for \(y\):
Divide each term by \(3\).
\[ y = \frac{6 - 2x}{3} \] -
Simplifying:
Split the fraction:
\[ y = \frac{6}{3} - \frac{2x}{3} \]
Which simplifies to:
\[ y = 2 - \frac{2}{3}x \]
You can also write this in slope-intercept form as:
\[
y = -\frac{2}{3}x + 2
\]
Thus, you have successfully isolated \(y\) in the equation:
\[
y = -\frac{2}{3}x + 2
\]