The volume of a cone is 261.8 cm cubed and the height of the cone is 10 cm. What is the approximate radius of the cone?

Use the `\pi` button in your calculations and round to the nearest whole.

1 answer

The formula for the volume \( V \) of a cone is given by:

\[ V = \frac{1}{3} \pi r^2 h \]

where \( r \) is the radius and \( h \) is the height of the cone. We know the volume \( V = 261.8 , \text{cm}^3 \) and the height \( h = 10 , \text{cm} \). We need to solve for the radius \( r \).

Substituting the known values into the volume formula, we have:

\[ 261.8 = \frac{1}{3} \pi r^2 (10) \]

This simplifies to:

\[ 261.8 = \frac{10}{3} \pi r^2 \]

Now, multiply both sides by \( 3 \) to eliminate the fraction:

\[ 3 \times 261.8 = 10 \pi r^2 \]

This results in:

\[ 785.4 = 10 \pi r^2 \]

Next, divide both sides by \( 10 \pi \):

\[ \frac{785.4}{10 \pi} = r^2 \]

Calculating \( \frac{785.4}{10} = 78.54 \), we have:

\[ r^2 = \frac{78.54}{\pi} \]

Now, using \( \pi \approx 3.14 \):

\[ r^2 = \frac{78.54}{3.14} \approx 25 \]

Taking the square root of both sides gives:

\[ r \approx \sqrt{25} \approx 5 \]

Thus, the approximate radius of the cone is:

\[ \boxed{5} , \text{cm} \]