Asked by Jone
Train A & B are traveling in the same direction on parelle tracks.Train A is traveling at 60mph, and train is traveling at 80mph.Train A passes a station at 10:25 A.M.If train B passes the some station at 10:37 A.M., what tine will train B catch-up with train A?
Answers
Answered by
bobpursley
so they are 12 minutes apart. Train A has traveled 12 miles in that time (d=v*t)
so, the relative distance is 12miles, at a relative velocity of 20mph, it takes
time=12/20=3/5 hr or 36 min, so the time of catching up is 36 min after 10:37
so, the relative distance is 12miles, at a relative velocity of 20mph, it takes
time=12/20=3/5 hr or 36 min, so the time of catching up is 36 min after 10:37
Answered by
Henry
10:37-10:25=12 minutes=0.2hour difference. When B catches up in 12
minutes, their distance traveled will
be equal: 60t=80(0.2), t=0.266666 hr
=16 minutes.
minutes, their distance traveled will
be equal: 60t=80(0.2), t=0.266666 hr
=16 minutes.
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