Question

Triangle ABC
𝐴
𝐵
𝐶
is reflected across the x
𝑥
-axis. If the coordinates of the original shape are A(−4,−1)
𝐴
(
−
4
,
−
1
)
, B(−5,−2)
𝐵
(
−
5
,
−
2
)
, and C(−10,−1)
𝐶
(
−
10
,
−
1
)
, what are the coordinates of A′
𝐴
′
, B′
𝐵
′
, and C′
𝐶
′
?(1 point)
Responses

A′(4,1)
𝐴
′
(
4
,
1
)
, B′(5,2)
𝐵
′
(
5
,
2
)
, and C′(10,1)
𝐶
′
(
10
,
1
)
upper A prime left parenthesis 4 comma 1 right parenthesis , upper B prime left parenthesis 5 comma 2 right parenthesis , and upper C prime left parenthesis 10 comma 1 right parenthesis

A′(−4,1)
𝐴
′
(
−
4
,
1
)
, B′(5,−2)
𝐵
′
(
5
,
−
2
)
, and C′(−10,1)
𝐶
′
(
−
10
,
1
)
upper A prime left parenthesis negative 4 comma 1 right parenthesis , upper B prime left parenthesis 5 comma negative 2 right parenthesis , and upper C prime left parenthesis negative 10 comma 1 right parenthesis

A′(−4,1)
𝐴
′
(
−
4
,
1
)
, B′(−5,2)
𝐵
′
(

Answer 1

When a point is reflected across the x-axis, the x-coordinate remains the same while the y-coordinate changes sign.

Given the original coordinates:
- A(−4,−1)
- B(−5,−2)
- C(−10,−1)

Reflecting these points across the x-axis, we have:

1. For point A(−4,−1):
- A′(−4, 1)

2. For point B(−5,−2):
- B′(−5, 2)

3. For point C(−10,−1):
- C′(−10, 1)

So the coordinates of A′, B′, and C′ are:
- A′(−4, 1)
- B′(−5, 2)
- C′(−10, 1)

Therefore, the correct response is:
**A′(−4, 1), B′(−5, 2), and C′(−10, 1)**.