To find the coordinates of the vertices for square A′B′C′D′ after reflecting it on the x-axis and then on the y-axis, we can perform the transformations based on the original coordinates of square ABCD.
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Original vertices:
- A(2, 4)
- B(2, 11)
- C(7, 11)
- D(7, 4)
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Reflection over the x-axis:
- A(2, 4) → A'(2, -4)
- B(2, 11) → B'(2, -11)
- C(7, 11) → C'(7, -11)
- D(7, 4) → D'(7, -4)
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Reflection over the y-axis:
- A'(2, -4) → A''(-2, -4)
- B'(2, -11) → B''(-2, -11)
- C'(7, -11) → C''(-7, -11)
- D'(7, -4) → D''(-7, -4)
Thus, after reflecting square ABCD over both axes, the coordinates of the vertices for square A′B′C′D′ are A''(-2, -4), B''(-2, -11), C''(-7, -11), and D''(-7, -4).
So, comparing with the options given:
Option A: Square A′B′C′D′ has vertices A′(−2,−4), B′(−2,−11), C′(−7,−11), and D′(−7,−4).
Option B: Square A′B′C′D′ has vertices A′(2,−4), B′(2,−11), C′(7,−11), and D′(7,−4).
The correct choice is Option A.