To find the vertices of square \( A'B'C'D' \) after reflecting square \( ABCD \) across the x-axis and then the y-axis, we will perform each reflection step-by-step.
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Reflection across the x-axis:
- A(2, 4) → A'(2, -4)
- B(2, 11) → B'(2, -11)
- C(7, 11) → C'(7, -11)
- D(7, 4) → D'(7, -4)
After reflecting across the x-axis, the coordinates of the vertices are:
- A'(2, -4)
- B'(2, -11)
- C'(7, -11)
- D'(7, -4)
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Reflection across the y-axis:
- A'(2, -4) → A''(-2, -4)
- B'(2, -11) → B''(-2, -11)
- C'(7, -11) → C''(-7, -11)
- D'(7, -4) → D''(-7, -4)
After reflecting across the y-axis, the final coordinates of the vertices are:
- A''(-2, -4)
- B''(-2, -11)
- C''(-7, -11)
- D''(-7, -4)
Comparing this with the provided options:
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Option A: Square \( A'B'C'D' \) has vertices A'(-2, -4), B'(-2, -11), C'(-7, -11), and D'(-7, -4). (This is correct)
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Option B: Square \( A'B'C'D' \) has vertices A'(2, -4), B'(2, -11), C'(7, -11), and D'(7, -4). (This is incorrect)
Thus, the correct option is Option A.