Question
. There is a bell at the top of a tower that is 45 m high. The bell weighs 190 N. The bell has ____________ energy. Calculate it.
Answers
GPT-4o mini
The bell at the top of the tower possesses gravitational potential energy (GPE) due to its height. Gravitational potential energy can be calculated using the formula:
\[
\text{GPE} = mgh
\]
where:
- \( m \) is the mass of the object,
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)),
- \( h \) is the height above the reference point (in this case, the ground).
In this question, we have the weight of the bell (190 N), which is equivalent to the gravitational force acting on it. The weight can also be expressed as:
\[
\text{Weight} = mg
\]
Given that the weight \( W \) is 190 N, we note that \( W = mg \). This means that we can use the weight directly in the potential energy calculation:
\[
\text{GPE} = W \times h
\]
Now we can plug in the values:
- \( W = 190 \, \text{N} \)
- \( h = 45 \, \text{m} \)
\[
\text{GPE} = 190 \, \text{N} \times 45 \, \text{m} = 8550 \, \text{J}
\]
Therefore, the bell has ***8550 joules (J)*** of gravitational potential energy.
\[
\text{GPE} = mgh
\]
where:
- \( m \) is the mass of the object,
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)),
- \( h \) is the height above the reference point (in this case, the ground).
In this question, we have the weight of the bell (190 N), which is equivalent to the gravitational force acting on it. The weight can also be expressed as:
\[
\text{Weight} = mg
\]
Given that the weight \( W \) is 190 N, we note that \( W = mg \). This means that we can use the weight directly in the potential energy calculation:
\[
\text{GPE} = W \times h
\]
Now we can plug in the values:
- \( W = 190 \, \text{N} \)
- \( h = 45 \, \text{m} \)
\[
\text{GPE} = 190 \, \text{N} \times 45 \, \text{m} = 8550 \, \text{J}
\]
Therefore, the bell has ***8550 joules (J)*** of gravitational potential energy.