Asked by burnout
Question
Use the functions below.
f(x)=2x−5
g(x)=|x|+2
h(x)=−3x
What is (f−g⋅h)(x)
? What is the domain of (f−g⋅h)(x)
?
(1 point)
Responses
(f−g⋅h)(x)=2x+3x|x|+6x−5
and the domain of (f−g⋅h)(x)
is (−∞, ∞)
.
open paren f minus g times h close paren times x is equal to 2 to the x th power plus 3 x divides x divides plus 6 x minus 5 and the domain of open paren f minus g times h close paren times x is open paren negative infinity comma infinity close paren .
(f−g⋅h)(x)=−3⋅2xx+3x|x|+21x
and the domain of (f−g⋅h)(x)
is x≠0
.
open paren f minus g times h close paren times x is equal to negative 3 times 2 to the x th power x plus 3 x divides x divides plus 21 x and the domain of open paren f minus g times h close paren times x is x is not equal to 0 .
(f−g⋅h)(x)=−3⋅2xx+3x|x|+21x
and the domain of (f−g⋅h)(x)
is (−∞, ∞)
.
open paren f minus g times h close paren times x is equal to negative 3 times 2 to the x th power x plus 3 x divides x divides plus 21 x and the domain of open paren f minus g times h close paren times x is open paren negative infinity comma infinity close paren .
(f−g⋅h)(x)=2x+3x|x|+6x−5
and the domain of (f−g⋅h)(x)
is x≠0
.
open paren f minus g times h close paren times x is equal to 2 to the x th power plus 3 x divides x divides plus 6 x minus 5 and the domain of open paren f minus g times h close paren times x is x is not equal to 0 .
Use the functions below.
f(x)=2x−5
g(x)=|x|+2
h(x)=−3x
What is (f−g⋅h)(x)
? What is the domain of (f−g⋅h)(x)
?
(1 point)
Responses
(f−g⋅h)(x)=2x+3x|x|+6x−5
and the domain of (f−g⋅h)(x)
is (−∞, ∞)
.
open paren f minus g times h close paren times x is equal to 2 to the x th power plus 3 x divides x divides plus 6 x minus 5 and the domain of open paren f minus g times h close paren times x is open paren negative infinity comma infinity close paren .
(f−g⋅h)(x)=−3⋅2xx+3x|x|+21x
and the domain of (f−g⋅h)(x)
is x≠0
.
open paren f minus g times h close paren times x is equal to negative 3 times 2 to the x th power x plus 3 x divides x divides plus 21 x and the domain of open paren f minus g times h close paren times x is x is not equal to 0 .
(f−g⋅h)(x)=−3⋅2xx+3x|x|+21x
and the domain of (f−g⋅h)(x)
is (−∞, ∞)
.
open paren f minus g times h close paren times x is equal to negative 3 times 2 to the x th power x plus 3 x divides x divides plus 21 x and the domain of open paren f minus g times h close paren times x is open paren negative infinity comma infinity close paren .
(f−g⋅h)(x)=2x+3x|x|+6x−5
and the domain of (f−g⋅h)(x)
is x≠0
.
open paren f minus g times h close paren times x is equal to 2 to the x th power plus 3 x divides x divides plus 6 x minus 5 and the domain of open paren f minus g times h close paren times x is x is not equal to 0 .
Answers
Answered by
GPT-4o mini
To find \((f - g \cdot h)(x)\), we first need to compute \(g \cdot h\) and then subtract that from \(f(x)\).
Given the functions:
- \(f(x) = 2x - 5\)
- \(g(x) = |x| + 2\)
- \(h(x) = -3x\)
First, let's compute \(g(x) \cdot h(x)\):
\[
g(x) \cdot h(x) = (|x| + 2) \cdot (-3x) = -3x(|x| + 2) = -3x|x| - 6x
\]
Next, we need to substitute this into \(f(x)\):
\[
f(x) - g(x) \cdot h(x) = (2x - 5) - (-3x|x| - 6x)
\]
Now, simplifying this:
\[
f(x) - g(x) \cdot h(x) = 2x - 5 + 3x|x| + 6x
\]
Combining the like terms gives us:
\[
f(x) - g(x) \cdot h(x) = (2x + 6x) + 3x|x| - 5 = 8x + 3x|x| - 5
\]
Thus, we have:
\[
(f - g \cdot h)(x) = 8x + 3x|x| - 5
\]
Now, let's analyze the domain of \((f - g \cdot h)(x)\):
- The functions \(f(x)\), \(g(x)\), and \(h(x)\) have no restrictions on their domains; hence, they are defined for all real \(x\).
Thus, the domain of \((f - g \cdot h)(x)\) is:
\[
(-\infty, \infty)
\]
Putting it all together, the answer is:
\[
(f - g \cdot h)(x) = 8x + 3x|x| - 5
\]
And the domain is:
\[
(-\infty, \infty)
\]
Given the functions:
- \(f(x) = 2x - 5\)
- \(g(x) = |x| + 2\)
- \(h(x) = -3x\)
First, let's compute \(g(x) \cdot h(x)\):
\[
g(x) \cdot h(x) = (|x| + 2) \cdot (-3x) = -3x(|x| + 2) = -3x|x| - 6x
\]
Next, we need to substitute this into \(f(x)\):
\[
f(x) - g(x) \cdot h(x) = (2x - 5) - (-3x|x| - 6x)
\]
Now, simplifying this:
\[
f(x) - g(x) \cdot h(x) = 2x - 5 + 3x|x| + 6x
\]
Combining the like terms gives us:
\[
f(x) - g(x) \cdot h(x) = (2x + 6x) + 3x|x| - 5 = 8x + 3x|x| - 5
\]
Thus, we have:
\[
(f - g \cdot h)(x) = 8x + 3x|x| - 5
\]
Now, let's analyze the domain of \((f - g \cdot h)(x)\):
- The functions \(f(x)\), \(g(x)\), and \(h(x)\) have no restrictions on their domains; hence, they are defined for all real \(x\).
Thus, the domain of \((f - g \cdot h)(x)\) is:
\[
(-\infty, \infty)
\]
Putting it all together, the answer is:
\[
(f - g \cdot h)(x) = 8x + 3x|x| - 5
\]
And the domain is:
\[
(-\infty, \infty)
\]
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