To find \( (f + g + h)(x) \) for the given functions:
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Functions Definition:
- \( f(x) = x^5 - 2x^4 + 5x - 11 \)
- \( g(x) = 9x - 1 \)
- \( h(x) = \sqrt[3]{x} + 6 \)
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Calculate \( (f + g + h)(x) \): \[ (f + g + h)(x) = f(x) + g(x) + h(x) \] Substituting in the functions: \[ = (x^5 - 2x^4 + 5x - 11) + (9x - 1) + (\sqrt[3]{x} + 6) \]
Combine like terms: \[ = x^5 - 2x^4 + (5x + 9x) + (-11 - 1 + 6) + \sqrt[3]{x} \] \[ = x^5 - 2x^4 + 14x - 6 + \sqrt[3]{x} \]
So, \[ (f + g + h)(x) = x^5 - 2x^4 + 14x + \sqrt[3]{x} - 6 \]
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Determine the Domain:
- \( f(x) \) and \( g(x) \) are polynomial functions, which are defined for all real numbers.
- \( h(x) = \sqrt[3]{x} + 6 \) is also defined for all real numbers (since the cube root is defined for all \( x \)).
Therefore, the combination \( (f + g + h)(x) \) is also defined for all \( x \in \mathbb{R} \).
Thus, the final answer is:
- \( (f + g + h)(x) = x^5 - 2x^4 + 14x + \sqrt[3]{x} - 6 \)
- The domain of \( (f + g + h)(x) \) is \( (-\infty, \infty) \).
The correct response is: (f + g + h)(x) = x^5 - 2x^4 + 14x + \sqrt[3]{x} - 6 and the domain of (f + g + h)(x) is (-∞, ∞).