To answer your question accurately, I need specific dimensions or additional details about the figure you’re referring to. However, I can guide you through the general steps to solve the problem.
(a) Finding the Area of the Smaller Rectangles
Assuming you have two smaller rectangles within the larger rectangle, let’s denote their dimensions as follows:
- Rectangle 1: Length \( l_1 \) and Width \( w_1 \)
- Rectangle 2: Length \( l_2 \) and Width \( w_2 \)
Area of Rectangle 1:
\[ \text{Area}_1 = l_1 \times w_1 \]
Area of Rectangle 2:
\[ \text{Area}_2 = l_2 \times w_2 \]
(b) Finding the Area of the Entire Figure
-
As a sum of two areas: \[ \text{Total Area} = \text{Area}_1 + \text{Area}_2 \] \[ \text{Total Area} = (l_1 \times w_1) + (l_2 \times w_2) \]
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As a product of the length and width:
- First, determine the overall length \( L \) and width \( W \) of the entire rectangle. This may involve adding the lengths or widths of the smaller rectangles, depending on how they are arranged (side by side or one on top of the other). \[ \text{Total Area} = L \times W \]
Example
If we assume:
- Rectangle 1: \( l_1 = 4 \) units, \( w_1 = 3 \) units
- Rectangle 2: \( l_2 = 2 \) units, \( w_2 = 5 \) units
-
Area of Rectangle 1:
\[ \text{Area}_1 = 4 \times 3 = 12 \text{ square units} \] -
Area of Rectangle 2:
\[ \text{Area}_2 = 2 \times 5 = 10 \text{ square units} \] -
Total Area as a sum of two areas:
\[ \text{Total Area} = 12 + 10 = 22 \text{ square units} \] -
If the total rectangle's dimensions are \( L = 4 \) and \( W = 8 \):
\[ \text{Total Area} = 4 \times 8 = 32 \text{ square units} \]
Please provide the specific dimensions or configuration of the rectangles if you want a more tailored answer.
2 answers