To find the missing value \( x \) that makes the point \( (__, 28) \) on the equation \( y = 6x - 4 \), we can substitute \( y \) with 28 and solve for \( x \).
Starting with the equation:
\[ y = 6x - 4 \]
Substituting \( y \) with 28 gives us:
\[ 28 = 6x - 4 \]
Next, we can add 4 to both sides:
\[ 28 + 4 = 6x \]
This simplifies to:
\[ 32 = 6x \]
Now, divide both sides by 6:
\[ x = \frac{32}{6} = \frac{16}{3} \approx 5.33 \]
Therefore, the missing value is:
\[ x = \frac{16}{3} \]
So the point \( \left(\frac{16}{3}, 28\right) \) lies on the equation \( y = 6x - 4 \).