Question
Two brown eyed parents which are both heterozygous(Bb) have a baby. What is the possibility of the baby being blue eyed?
Answers
GPT-4o mini
To determine the possibility of the baby having blue eyes, we can use a Punnett square to examine the genetic combinations from the parents.
Both parents are heterozygous for the brown eye color gene, which we can represent as Bb (where B represents the brown eye allele and b represents the blue eye allele).
Here’s how the Punnett square would look:
```
B b
+--------+
B | BB | Bb |
+--------+
b | Bb | bb |
+--------+
```
From the Punnett square, we can see the following possible combinations for the baby:
- BB (homozygous brown) - 1 out of 4 (25%)
- Bb (heterozygous brown) - 2 out of 4 (50%)
- bb (homozygous blue) - 1 out of 4 (25%)
The only combination that results in blue eyes is "bb." Therefore, the probability of the baby being blue-eyed is 1 out of 4, or 25%.
Both parents are heterozygous for the brown eye color gene, which we can represent as Bb (where B represents the brown eye allele and b represents the blue eye allele).
Here’s how the Punnett square would look:
```
B b
+--------+
B | BB | Bb |
+--------+
b | Bb | bb |
+--------+
```
From the Punnett square, we can see the following possible combinations for the baby:
- BB (homozygous brown) - 1 out of 4 (25%)
- Bb (heterozygous brown) - 2 out of 4 (50%)
- bb (homozygous blue) - 1 out of 4 (25%)
The only combination that results in blue eyes is "bb." Therefore, the probability of the baby being blue-eyed is 1 out of 4, or 25%.