Question
Factors that Affect Kinetic Energy Quick Check
3 of 53 of 5 Items
Question
A student rides her bicycle down a hill. Together, she and the bicycle have a mass of 56 kilograms. She is moving at 11 meters per second. What is her kinetic energy?(1 point)
Responses
6,776 J
6,776 J
3,388 J
3,388 J
13,552 J
13,552 J
17,248 J
17,248 J
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3 of 53 of 5 Items
Question
A student rides her bicycle down a hill. Together, she and the bicycle have a mass of 56 kilograms. She is moving at 11 meters per second. What is her kinetic energy?(1 point)
Responses
6,776 J
6,776 J
3,388 J
3,388 J
13,552 J
13,552 J
17,248 J
17,248 J
Skip to navigation
Answers
GPT-4o mini
To calculate the kinetic energy (KE) of the student riding her bicycle, you can use the formula:
\[
KE = \frac{1}{2} mv^2
\]
where:
- \(m\) is the mass in kilograms,
- \(v\) is the velocity in meters per second.
Given:
- \(m = 56\) kg
- \(v = 11\) m/s
Let's plug in the values:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times (11 \, \text{m/s})^2
\]
First, calculate \( (11 \, \text{m/s})^2 \):
\[
(11 \, \text{m/s})^2 = 121 \, \text{m}^2/\text{s}^2
\]
Now, substitute that back into the equation:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times 121 \, \text{m}^2/\text{s}^2
\]
Calculate \( \frac{1}{2} \times 56 = 28\):
\[
KE = 28 \, \text{kg} \times 121 \, \text{m}^2/\text{s}^2 = 3,388 \, \text{J}
\]
Therefore, the kinetic energy of the student and her bicycle is **3,388 J**.
The correct response is:
**3,388 J**.
\[
KE = \frac{1}{2} mv^2
\]
where:
- \(m\) is the mass in kilograms,
- \(v\) is the velocity in meters per second.
Given:
- \(m = 56\) kg
- \(v = 11\) m/s
Let's plug in the values:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times (11 \, \text{m/s})^2
\]
First, calculate \( (11 \, \text{m/s})^2 \):
\[
(11 \, \text{m/s})^2 = 121 \, \text{m}^2/\text{s}^2
\]
Now, substitute that back into the equation:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times 121 \, \text{m}^2/\text{s}^2
\]
Calculate \( \frac{1}{2} \times 56 = 28\):
\[
KE = 28 \, \text{kg} \times 121 \, \text{m}^2/\text{s}^2 = 3,388 \, \text{J}
\]
Therefore, the kinetic energy of the student and her bicycle is **3,388 J**.
The correct response is:
**3,388 J**.