Asked by theo
Calculate dy/dt using the given information.
(x+y)/(x-y)= x^2 + y^2; dx/dt = 12, x = 1, y = 0
(x+y)/(x-y)= x^2 + y^2; dx/dt = 12, x = 1, y = 0
Answers
Answered by
bobpursley
multipy both sides by (x-y)
x+y=x^3 -yx^2-xy^2-y^3 check that.
dx/dt+dy/dt= 3x^2 dx/dt-2yx dx/dt-x^2dy/dt-y^2dx/dt-3y^2 dy/dt
gather terms....
dx/dt(1-3x^2+2yx+3y^2)=dy/dt (-1-x^2-3y^2)
check that carefully, it is easy to make an error in sign.
solve for dy/dt
x+y=x^3 -yx^2-xy^2-y^3 check that.
dx/dt+dy/dt= 3x^2 dx/dt-2yx dx/dt-x^2dy/dt-y^2dx/dt-3y^2 dy/dt
gather terms....
dx/dt(1-3x^2+2yx+3y^2)=dy/dt (-1-x^2-3y^2)
check that carefully, it is easy to make an error in sign.
solve for dy/dt
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