Asked by P

I have to use my answer from a previous question (factorise and solve x^2+x-30=0 which i factorised as (x-5)(x+6)=0 and then solved as x=5 or x=-6) i now have to explain how i can use this answer to solve th equation 4x^2+4x-120=0 and then say what are the solutions?

Please could you help me!!!!!
Thank you

Answers

Answered by Quidditch
Do you see a numeric factor that is common in each term? Factor that number from each term. What is left?
Answered by PsyDAG
Substitute each value in the second equation to see what fits.
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