Question
The graph shows the distance a skydiver falls over time once she reaches maximum speed.
Enter values to complete each statement below based on the graph.
A graph titled distance a skydiver falls has time (seconds) on the x-axis, and distance (feet) on the y-axis. A line goes through (0, 0) and (1.5, 300).
Clear Check
In one second, a skydiver falls
feet.
The unit rate is
feet per second.
Enter values to complete each statement below based on the graph.
A graph titled distance a skydiver falls has time (seconds) on the x-axis, and distance (feet) on the y-axis. A line goes through (0, 0) and (1.5, 300).
Clear Check
In one second, a skydiver falls
feet.
The unit rate is
feet per second.
Answers
Answered by
GPT-4o mini
Based on the information provided about the graph, we can interpret the points given.
The graph shows that at \( (0, 0) \), the distance fallen is 0 feet when the time is 0 seconds, and at \( (1.5, 300) \), the distance fallen is 300 feet at 1.5 seconds.
1. To find out how far the skydiver falls in one second, we can calculate the distance fallen from the point \( (0, 0) \) to \( (1.5, 300) \). The distance fallen over the time interval of 1.5 seconds is 300 feet.
- To find the distance fallen in the first 1 second, we note that the graph is linear between these two points, so we can determine that the distance fallen in 1 second is proportional to the distance at 1 second. Since the total distance after 1.5 seconds is 300 feet, we can find the distance at 1 second by calculating \( \frac{300}{1.5} \):
\[
\text{Distance in 1 second} = \frac{300 \text{ feet}}{1.5} \cdot 1 = 200 \text{ feet}
\]
**In one second, a skydiver falls 200 feet.**
2. To find the unit rate, we need to determine the average speed or rate of falling per second. Since the total distance is 300 feet over 1.5 seconds, the unit rate can be calculated by dividing the total distance by the total time:
\[
\text{Unit Rate} = \frac{300 \text{ feet}}{1.5 \text{ seconds}} = 200 \text{ feet per second}
\]
**The unit rate is 200 feet per second.**
So the completed statements would be:
- In one second, a skydiver falls **200** feet.
- The unit rate is **200** feet per second.
The graph shows that at \( (0, 0) \), the distance fallen is 0 feet when the time is 0 seconds, and at \( (1.5, 300) \), the distance fallen is 300 feet at 1.5 seconds.
1. To find out how far the skydiver falls in one second, we can calculate the distance fallen from the point \( (0, 0) \) to \( (1.5, 300) \). The distance fallen over the time interval of 1.5 seconds is 300 feet.
- To find the distance fallen in the first 1 second, we note that the graph is linear between these two points, so we can determine that the distance fallen in 1 second is proportional to the distance at 1 second. Since the total distance after 1.5 seconds is 300 feet, we can find the distance at 1 second by calculating \( \frac{300}{1.5} \):
\[
\text{Distance in 1 second} = \frac{300 \text{ feet}}{1.5} \cdot 1 = 200 \text{ feet}
\]
**In one second, a skydiver falls 200 feet.**
2. To find the unit rate, we need to determine the average speed or rate of falling per second. Since the total distance is 300 feet over 1.5 seconds, the unit rate can be calculated by dividing the total distance by the total time:
\[
\text{Unit Rate} = \frac{300 \text{ feet}}{1.5 \text{ seconds}} = 200 \text{ feet per second}
\]
**The unit rate is 200 feet per second.**
So the completed statements would be:
- In one second, a skydiver falls **200** feet.
- The unit rate is **200** feet per second.