Question

writing linear eqautions from standard form to slope-intercept form
4x-y=1

Answer 1

correct

Answer 2

To convert the equation from standard form \( Ax + By = C \) to slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept, you can follow these steps.

Given the equation:
\[ 4x - y = 1 \]

1. Start by isolating \( y \). You can do this by moving \( 4x \) to the right side of the equation:
\[ -y = -4x + 1 \]

2. Next, multiply through by -1 to solve for \( y \):
\[ y = 4x - 1 \]

Now the equation is in slope-intercept form \( y = mx + b \), where \( m = 4 \) and \( b = -1 \).

Thus, the slope-intercept form of the equation \( 4x - y = 1 \) is:
\[ y = 4x - 1 \]