To calculate the kinetic energy (KE) of the suitcase just before it hits the floor, you can use the formula:
\[ KE = \frac{1}{2} mv^2 \]
where:
- \( m \) is the mass of the suitcase (14 kg),
- \( v \) is the velocity of the suitcase (2.7 m/s).
Plugging in the values:
\[ KE = \frac{1}{2} \times 14 , \text{kg} \times (2.7 , \text{m/s})^2 \]
Calculating \( (2.7 , \text{m/s})^2 \):
\[ (2.7 , \text{m/s})^2 = 7.29 , \text{m}^2/\text{s}^2 \]
Now substituting this into the kinetic energy equation:
\[ KE = \frac{1}{2} \times 14 , \text{kg} \times 7.29 , \text{m}^2/\text{s}^2 \]
\[ KE = 7 \times 7.29 , \text{kg} \cdot \text{m}^2/\text{s}^2 \]
\[ KE = 51.03 , \text{J} \]
So the kinetic energy of the suitcase just before it hits the floor is 51.03 J.
The correct response is: 51.03 J