Question
A 10-volt power supply is placed in series with two 5-ohm resistors. What is the current in the circuit after
it passes through each of the two resistors?
answers below:
The current will stay the same at 2 amps after passing through both resistors.
The current will drop to 1 amp after the first resistor and then to 0 amps after the second resistor.
The current will drop to 2 amps after the first resistor and then to 1 amp after the second resistor.
The current will stay the same at 1 amp after passing through both resistors.
it passes through each of the two resistors?
answers below:
The current will stay the same at 2 amps after passing through both resistors.
The current will drop to 1 amp after the first resistor and then to 0 amps after the second resistor.
The current will drop to 2 amps after the first resistor and then to 1 amp after the second resistor.
The current will stay the same at 1 amp after passing through both resistors.
Answers
GPT-4o mini
To solve for the current in the circuit, we first need to find the total resistance and then apply Ohm's Law.
1. **Determine total resistance**: Since the two resistors (5 ohms each) are in series, the total resistance \( R_t \) can be calculated as:
\[
R_t = R_1 + R_2 = 5 \, \Omega + 5 \, \Omega = 10 \, \Omega
\]
2. **Calculate the total current using Ohm's Law**: Ohm's Law states \( V = I \cdot R \), which can be rearranged to find current \( I \):
\[
I = \frac{V}{R_t} = \frac{10 \, \text{V}}{10 \, \Omega} = 1 \, \text{A}
\]
In a series circuit, the current remains the same after passing through each component. Therefore, the current does not change after passing through either of the two 5-ohm resistors.
Thus, the correct answer is:
**The current will stay the same at 1 amp after passing through both resistors.**
1. **Determine total resistance**: Since the two resistors (5 ohms each) are in series, the total resistance \( R_t \) can be calculated as:
\[
R_t = R_1 + R_2 = 5 \, \Omega + 5 \, \Omega = 10 \, \Omega
\]
2. **Calculate the total current using Ohm's Law**: Ohm's Law states \( V = I \cdot R \), which can be rearranged to find current \( I \):
\[
I = \frac{V}{R_t} = \frac{10 \, \text{V}}{10 \, \Omega} = 1 \, \text{A}
\]
In a series circuit, the current remains the same after passing through each component. Therefore, the current does not change after passing through either of the two 5-ohm resistors.
Thus, the correct answer is:
**The current will stay the same at 1 amp after passing through both resistors.**