To simplify the expression \( 2(x+3) + 4(x+1) \), we'll distribute the constants across the terms inside the parentheses:
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Distribute \( 2 \) to \( (x + 3) \): \[ 2(x + 3) = 2x + 6 \]
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Distribute \( 4 \) to \( (x + 1) \): \[ 4(x + 1) = 4x + 4 \]
Now, we can combine these results: \[ 2x + 6 + 4x + 4 \]
Next, combine the like terms \( 2x \) and \( 4x \): \[ 2x + 4x = 6x \]
Now, combine the constant terms \( 6 \) and \( 4 \): \[ 6 + 4 = 10 \]
Putting it all together, we have: \[ 6x + 10 \]
So, the expression equivalent to \( 2(x+3) + 4(x+1) \) is: \[ \boxed{6x + 10} \]
Thus, the correct response is 6x + 10.