Question

Cynthia is writing a program in which the user will have three choices and the code will be executed differently based on the user's Choice which statement should be used to accomplish this? A. first, second, third

Answer 1

To handle multiple choices in a program based on user input, you should use a control structure that allows branching based on the user's selection. Common choices for this purpose are:

1. **If-elif-else statements**: This is ideal for when you have multiple distinct conditions to check.
2. **Switch-case statements**: This is a clear choice for languages that support it (like C, Java, etc.), usually when you have many conditions based on a single variable’s value.

Since you mentioned "three choices", the `if-elif-else` structure is commonly used in Python.

Here is a basic example in Python:

```python
user_choice = input("Enter your choice (first/second/third): ")

if user_choice == "first":
# Execute code for first choice
print("You selected the first option.")
elif user_choice == "second":
# Execute code for second choice
print("You selected the second option.")
elif user_choice == "third":
# Execute code for third choice
print("You selected the third option.")
else:
print("Invalid choice.")
```

If you're using a language with a `switch` statement capability, it would look something like this in C:

```c
#include <stdio.h>

int main() {
int choice;
printf("Enter your choice (1 for first, 2 for second, 3 for third): ");
scanf("%d", &choice);

switch (choice) {
case 1:
// Execute code for first choice
printf("You selected the first option.\n");
break;
case 2:
// Execute code for second choice
printf("You selected the second option.\n");
break;
case 3:
// Execute code for third choice
printf("You selected the third option.\n");
break;
default:
printf("Invalid choice.\n");
}

return 0;
}
```

Choose the method that matches your programming language and preference.