13. A series circuit is formed with a 10-V power supply and two resistors, where R 1

Question

= 6 ohms and R 2
= 4 ohms. The current through the resistors is I 1
and I 2
, respectively. What are the values of I 1
and I 2
?(1 point)
Responses

I1
= I2
= 1.0 A
I 1 = I 2 = 1.0 A

I1
= I2
= 0.5 A
I 1 = I 2 = 0.5 A

I1
= 1.67 A; I2
= 2.5 A
I 1 = 1.67 A; I 2 = 2.5 A

I1
= 0.6 A; I2
= 0.4 A

Answer 1

In a series circuit, the current flowing through each component is the same. Thus, \(I_1 = I_2 = I\).

First, we need to find the total resistance \(R_{total}\) in the series circuit:

\[ R_{total} = R_1 + R_2 = 6, \Omega + 4, \Omega = 10, \Omega \]

Now, we can use Ohm's Law to find the current. Ohm's Law states:

\[ V = I \cdot R \]

Rearranging this gives:

\[ I = \frac{V}{R} \]

Substituting the values we have:

\[ I = \frac{10, V}{10, \Omega} = 1, A \]

So, \(I_1 = I_2 = 1, A\).

The correct response is:

I1 = I2 = 1.0 A