Convert the equation y=5(x+2)^2−6 from vertex form to standard form.(1 point)

Answer 1

To convert the equation \( y = 5(x + 2)^2 - 6 \) from vertex form to standard form, we need to expand the equation.

1. Start with the equation: \[ y = 5(x + 2)^2 - 6 \]

2. Expand \( (x + 2)^2 \): \[ (x + 2)^2 = x^2 + 4x + 4 \]

3. Substitute this back into the equation: \[ y = 5(x^2 + 4x + 4) - 6 \]

4. Distribute the \( 5 \): \[ y = 5x^2 + 20x + 20 - 6 \]

5. Combine like terms: \[ y = 5x^2 + 20x + 14 \]

Now the equation in standard form is: \[ y = 5x^2 + 20x + 14 \]