Question
Add the rational expressions to find the sum: x^2−2/3x−2+x+5/3x−2
.(1 point)
Responses
x^3+3/3x−2
Start Fraction x cubed plus 3 over 3 x minus 2 End Fraction
x^2+x+7/3x−2
Start Fraction x squared plus x plus 7 over 3 x minus 2 End Fraction
x^2+x+3/3x−2
Start Fraction x squared plus x plus 3 over 3 x minus 2 End Fraction
x^2+x+3/6x−4
Start Fraction x squared plus x plus 3 over 6 x minus 4 End Fraction
Skip to navigation
.(1 point)
Responses
x^3+3/3x−2
Start Fraction x cubed plus 3 over 3 x minus 2 End Fraction
x^2+x+7/3x−2
Start Fraction x squared plus x plus 7 over 3 x minus 2 End Fraction
x^2+x+3/3x−2
Start Fraction x squared plus x plus 3 over 3 x minus 2 End Fraction
x^2+x+3/6x−4
Start Fraction x squared plus x plus 3 over 6 x minus 4 End Fraction
Skip to navigation
Answers
GPT-4o mini
To add the two rational expressions \(\frac{x^2 - 2}{3x - 2}\) and \(\frac{x + 5}{3x - 2}\), we can combine them since they already have a common denominator.
The expression will look like this:
\[
\frac{x^2 - 2}{3x - 2} + \frac{x + 5}{3x - 2} = \frac{(x^2 - 2) + (x + 5)}{3x - 2}
\]
Now, we will simplify the numerator:
1. Combine terms in the numerator:
\[
(x^2 - 2) + (x + 5) = x^2 + x + 3
\]
So, the combined expression is:
\[
\frac{x^2 + x + 3}{3x - 2}
\]
Thus, the sum of the rational expressions is:
\[
\frac{x^2 + x + 3}{3x - 2}
\]
From the options provided, this matches with:
\[
\text{Start Fraction x squared plus x plus 3 over 3 x minus 2 End Fraction}
\]
So the correct answer is:
\(\frac{x^2 + x + 3}{3x - 2}\)
The expression will look like this:
\[
\frac{x^2 - 2}{3x - 2} + \frac{x + 5}{3x - 2} = \frac{(x^2 - 2) + (x + 5)}{3x - 2}
\]
Now, we will simplify the numerator:
1. Combine terms in the numerator:
\[
(x^2 - 2) + (x + 5) = x^2 + x + 3
\]
So, the combined expression is:
\[
\frac{x^2 + x + 3}{3x - 2}
\]
Thus, the sum of the rational expressions is:
\[
\frac{x^2 + x + 3}{3x - 2}
\]
From the options provided, this matches with:
\[
\text{Start Fraction x squared plus x plus 3 over 3 x minus 2 End Fraction}
\]
So the correct answer is:
\(\frac{x^2 + x + 3}{3x - 2}\)