To find the equation of the line that passes through the points (3, -2) and (6, 2), we first need to calculate the slope (m) of the line using the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Using the points (x₁, y₁) = (3, -2) and (x₂, y₂) = (6, 2):
\[ m = \frac{2 - (-2)}{6 - 3} = \frac{2 + 2}{3} = \frac{4}{3} \]
Now that we have the slope, we can write the equation of the line in point-slope form, which is given by:
\[ y - y_1 = m(x - x_1) \]
Using point (3, -2):
\[ y - (-2) = \frac{4}{3}(x - 3) \] This simplifies to:
\[ y + 2 = \frac{4}{3}(x - 3) \]
Next, we will convert this equation to standard form (Ax + By = C) by rearranging and clearing any fractions. First, let's expand and simplify:
\[ y + 2 = \frac{4}{3}x - \frac{4}{3} \cdot 3 \] \[ y + 2 = \frac{4}{3}x - 4 \]
Now, to isolate \(y\), we subtract 2 from both sides:
\[ y = \frac{4}{3}x - 6 \]
Next, we'll move all terms to one side to create the standard form. To eliminate the fraction, we can multiply the entire equation by 3:
\[ 3y = 4x - 18 \]
Now, rearranging gives:
\[ 4x - 3y = 18 \]
Therefore, the equation of the line in standard form is:
\[ 4x - 3y = 18 \]
To summarize, the final equations are:
- Point-slope form: \(y + 2 = \frac{4}{3}(x - 3)\)
- Standard form: \(4x - 3y = 18\)