The point-slope form of a linear equation is given by the formula:
\[ y - y_1 = m(x - x_1) \]
where \((x_1, y_1)\) is a point on the line and \(m\) is the slope.
Given the point \((9, -1)\) and the slope \(m = \frac{4}{3}\), we can substitute these values into the formula:
- \(x_1 = 9\)
- \(y_1 = -1\)
- \(m = \frac{4}{3}\)
Now substituting these into the equation:
\[ y - (-1) = \frac{4}{3}(x - 9) \]
This simplifies to:
\[ y + 1 = \frac{4}{3}(x - 9) \]
So the equation in point-slope form is:
\[ y + 1 = \frac{4}{3}(x - 9) \]
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