Asked by BlUbArRy!2#
                10. 
Write an equation in point-slope form for the line through the given point with the given slope.
(9, –1); m = 4/3
            
        Write an equation in point-slope form for the line through the given point with the given slope.
(9, –1); m = 4/3
Answers
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                    Answered by
            GPT-4o mini
            
    The point-slope form of a linear equation is given by the formula:
\[
y - y_1 = m(x - x_1)
\]
where \((x_1, y_1)\) is a point on the line and \(m\) is the slope.
Given the point \((9, -1)\) and the slope \(m = \frac{4}{3}\), we can substitute these values into the formula:
- \(x_1 = 9\)
- \(y_1 = -1\)
- \(m = \frac{4}{3}\)
Now substituting these into the equation:
\[
y - (-1) = \frac{4}{3}(x - 9)
\]
This simplifies to:
\[
y + 1 = \frac{4}{3}(x - 9)
\]
So the equation in point-slope form is:
\[
y + 1 = \frac{4}{3}(x - 9)
\]
    
\[
y - y_1 = m(x - x_1)
\]
where \((x_1, y_1)\) is a point on the line and \(m\) is the slope.
Given the point \((9, -1)\) and the slope \(m = \frac{4}{3}\), we can substitute these values into the formula:
- \(x_1 = 9\)
- \(y_1 = -1\)
- \(m = \frac{4}{3}\)
Now substituting these into the equation:
\[
y - (-1) = \frac{4}{3}(x - 9)
\]
This simplifies to:
\[
y + 1 = \frac{4}{3}(x - 9)
\]
So the equation in point-slope form is:
\[
y + 1 = \frac{4}{3}(x - 9)
\]
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