Find the surface area of a textbook that is 2 in. × 14 in. × 9 in. (1 point) Responses 252 in.2 252 in. squared 50 in.2 50 in. squared 172 in.2 172 in. squared 344 in.2 344 in. squared

1 answer

To find the surface area of a rectangular prism (which is what a textbook is), you can use the formula:

\[ \text{Surface Area} = 2(lw + lh + wh) \]

where \( l \) is the length, \( w \) is the width, and \( h \) is the height.

Given dimensions:

  • \( l = 14 \) in.
  • \( w = 2 \) in.
  • \( h = 9 \) in.

Now substitute the values into the formula:

\[ lw = 14 \times 2 = 28 \quad (\text{length × width}) \] \[ lh = 14 \times 9 = 126 \quad (\text{length × height}) \] \[ wh = 2 \times 9 = 18 \quad (\text{width × height}) \]

Now plug these values into the surface area formula:

\[ \text{Surface Area} = 2(28 + 126 + 18) \] \[ = 2(172) \] \[ = 344 \text{ in.}^2 \]

Thus, the surface area of the textbook is 344 in.².