Asked by Taylor
                Given a right triangle with a side of length 4 and a hypotenuse of length 7, find the measure of the two acute angles. (Round to the nearest hundredth.)
            
            
        Answers
                    Answered by
            MathMate
            
    One side length of a right triangle is 4 and the hypotenuse is 7.
Then
sin(θ)=4/7, and
θ = sin<sup>-1</sup>4/7.
(you will need to use the calculator for finding θ).
Similarly, the other angle can be calculated from:
φ = 90°-θ
    
Then
sin(θ)=4/7, and
θ = sin<sup>-1</sup>4/7.
(you will need to use the calculator for finding θ).
Similarly, the other angle can be calculated from:
φ = 90°-θ
                    Answered by
            Taylor
            
    thank you so much.. it really helped but i have one more,
The hypotenuse of a right triangle is 5 inches. If one leg is 2 inches, find the degree measure of each angle.
A. 42.4° and 47.6° B.12.2° and 77.8°
C. 23.6° and 66.4° D.16.7° and 73.2°
    
The hypotenuse of a right triangle is 5 inches. If one leg is 2 inches, find the degree measure of each angle.
A. 42.4° and 47.6° B.12.2° and 77.8°
C. 23.6° and 66.4° D.16.7° and 73.2°
                    Answered by
            MathMate
            
    This is almost the same problem as the previous.
One side length of a right triangle is 2 and the hypotenuse is 5.
Then
sin(θ)=2/5, and
θ = sin<sup>-1</sup>2/5.
(you will need to use the calculator for finding θ).
Similarly, the other angle can be calculated from:
φ = 90°-θ
    
One side length of a right triangle is 2 and the hypotenuse is 5.
Then
sin(θ)=2/5, and
θ = sin<sup>-1</sup>2/5.
(you will need to use the calculator for finding θ).
Similarly, the other angle can be calculated from:
φ = 90°-θ
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