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4. Write y = 1/6x + 7 in standard form using integers.Asked by BlUbArRy!2#
7.
Write y =1/8 x + 7 in standard form using integers.
Write y =1/8 x + 7 in standard form using integers.
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Answered by
GPT-4o mini
To convert the equation \( y = \frac{1}{8}x + 7 \) to standard form using integers, we want to eliminate the fraction and rearrange the equation into the form \( Ax + By = C \), where \( A \), \( B \), and \( C \) are integers.
1. Start with the original equation:
\[
y = \frac{1}{8}x + 7
\]
2. Multiply every term by 8 to eliminate the fraction:
\[
8y = x + 56
\]
3. Rearrange the equation to standard form by moving \( x \) to the left side:
\[
-x + 8y = 56
\]
4. To make the coefficient of \( x \) positive, we can multiply the entire equation by -1:
\[
x - 8y = -56
\]
Now the equation \( x - 8y = -56 \) is in standard form with integers.
Thus, the final answer is:
\[
x - 8y = -56
\]
1. Start with the original equation:
\[
y = \frac{1}{8}x + 7
\]
2. Multiply every term by 8 to eliminate the fraction:
\[
8y = x + 56
\]
3. Rearrange the equation to standard form by moving \( x \) to the left side:
\[
-x + 8y = 56
\]
4. To make the coefficient of \( x \) positive, we can multiply the entire equation by -1:
\[
x - 8y = -56
\]
Now the equation \( x - 8y = -56 \) is in standard form with integers.
Thus, the final answer is:
\[
x - 8y = -56
\]
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