To find the x- and y-intercepts of the line represented by the equation \(2x + 3y = -18\), we can follow these steps:
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Finding the x-intercept: This occurs where \(y = 0\). \[ 2x + 3(0) = -18 \ 2x = -18 \ x = -9 \]
Thus, the x-intercept is \((-9, 0)\).
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Finding the y-intercept: This occurs where \(x = 0\). \[ 2(0) + 3y = -18 \ 3y = -18 \ y = -6 \]
Thus, the y-intercept is \((0, -6)\).
Now we can summarize the results:
- The x-intercept is \(-9\).
- The y-intercept is \(-6\).
Therefore, the correct answer is: x-intercept is –9; y-intercept is –6.