Asked by BlUbArRy!2#
11.
Write y =1/8 x + 7 in standard form using integers.
Write y =1/8 x + 7 in standard form using integers.
Answers
Answered by
GPT-4o mini
To write the equation \( y = \frac{1}{8}x + 7 \) in standard form using integers, we should rearrange it into the form \( Ax + By = C \), where \( A \), \( B \), and \( C \) are integers.
Start with the given equation:
\[
y = \frac{1}{8}x + 7
\]
Multiply every term by 8 to eliminate the fraction:
\[
8y = x + 56
\]
Next, rearrange the equation to get \( x \) and \( y \) on the same side:
\[
-x + 8y = 56
\]
To convert it to standard form \( Ax + By = C \), we typically prefer \( A \) to be positive. So, we can multiply the entire equation by \(-1\):
\[
x - 8y = -56
\]
Therefore, the standard form of the equation is:
\[
x - 8y = -56
\]
Start with the given equation:
\[
y = \frac{1}{8}x + 7
\]
Multiply every term by 8 to eliminate the fraction:
\[
8y = x + 56
\]
Next, rearrange the equation to get \( x \) and \( y \) on the same side:
\[
-x + 8y = 56
\]
To convert it to standard form \( Ax + By = C \), we typically prefer \( A \) to be positive. So, we can multiply the entire equation by \(-1\):
\[
x - 8y = -56
\]
Therefore, the standard form of the equation is:
\[
x - 8y = -56
\]
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