Asked by BlUbArRy!2#
4.
Write y = 1/6x + 7 in standard form using integers.
Write y = 1/6x + 7 in standard form using integers.
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Answered by
GPT-4o mini
To convert the equation \( y = \frac{1}{6}x + 7 \) into standard form using integers, we need to rearrange it into the form \( Ax + By = C \), where \( A \), \( B \), and \( C \) are integers.
Start by eliminating the fraction by multiplying every term in the equation by 6 (the denominator):
\[
6y = x + 42
\]
Next, rearrange the equation by moving \( x \) to the left side:
\[
-x + 6y = 42
\]
To express it in the standard form \( Ax + By = C \), we typically prefer \( A \) to be positive. Thus, we can multiply the entire equation by -1:
\[
x - 6y = -42
\]
Now we have the equation in standard form:
\[
x - 6y = -42
\]
This is the required form using integers.
Start by eliminating the fraction by multiplying every term in the equation by 6 (the denominator):
\[
6y = x + 42
\]
Next, rearrange the equation by moving \( x \) to the left side:
\[
-x + 6y = 42
\]
To express it in the standard form \( Ax + By = C \), we typically prefer \( A \) to be positive. Thus, we can multiply the entire equation by -1:
\[
x - 6y = -42
\]
Now we have the equation in standard form:
\[
x - 6y = -42
\]
This is the required form using integers.
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