2.

Question

Evaluate ƒ(x) = –x2 + 1 for x = –3.

–8

–4

–9

4

Answer 1

To evaluate the function \( f(x) = -x^2 + 1 \) for \( x = -3 \), we substitute \(-3\) into the function:

\[ f(-3) = -(-3)^2 + 1 \]

Calculating \((-3)^2\):

\[ (-3)^2 = 9 \]

Now substituting back into the function:

\[ f(-3) = -9 + 1 \]

Now, simplifying:

\[ f(-3) = -8 \]

Thus, the value of \( f(-3) \) is \(-8\). The correct choice is:

–8