Asked by ef
What is the temperature change of the sodium chloride pack?
ΔT = Tf - Ti
ΔT = 21°C - 4°C = 17°C
What is the energy change of the sodium chloride pack?
ΔE = 4 kJ/mol
Blank 1 (Starting Temperature):
21
Blank 2 (Change in Temperature):
4
Blank 3 (Ending Temperature):
17
Blank 4:
4
Question 2
Is this reaction endothermic or exothermic?
a
Endothermic
b
Exothermic
Question 3
Does this reaction make a hot or cold pack?
a
Hot pack
b
Cold pack
ΔT = Tf - Ti
ΔT = 21°C - 4°C = 17°C
What is the energy change of the sodium chloride pack?
ΔE = 4 kJ/mol
Blank 1 (Starting Temperature):
21
Blank 2 (Change in Temperature):
4
Blank 3 (Ending Temperature):
17
Blank 4:
4
Question 2
Is this reaction endothermic or exothermic?
a
Endothermic
b
Exothermic
Question 3
Does this reaction make a hot or cold pack?
a
Hot pack
b
Cold pack
Answers
Answered by
GPT-4o mini
Let's go through your questions step by step.
### Temperature Change Calculation:
You correctly calculated the temperature change (ΔT) as follows:
ΔT = Tf - Ti
ΔT = 21°C - 4°C = 17°C
### Energy Change:
It appears you have identified an energy change (ΔE), but you should ensure that this is consistent with the temperature change being calculated.
### Filling in the Blanks:
- **Blank 1 (Starting Temperature)**: **4°C** (this should reflect the initial temperature)
- **Blank 2 (Change in Temperature)**: **17°C** (this is the change you calculated)
- **Blank 3 (Ending Temperature)**: **21°C** (the final temperature after the change)
- **Blank 4**: **4 kJ/mol** (this is the energy change, assuming it's the energy change associated with the reaction)
### Question 2 - Endothermic or Exothermic?
- The reaction is **endothermic** (a). An endothermic reaction absorbs heat, which is consistent with a temperature decrease in the surroundings (like in a cold pack).
### Question 3 - Hot or Cold Pack?
- This reaction makes a **cold pack** (b). Since it's endothermic, it absorbs heat from its surroundings, making it feel cold.
### Summary:
- **Blank 1**: 4°C
- **Blank 2**: 17°C
- **Blank 3**: 21°C
- **Blank 4**: 4 kJ/mol
- **Question 2 Answer**: a (Endothermic)
- **Question 3 Answer**: b (Cold pack)
### Temperature Change Calculation:
You correctly calculated the temperature change (ΔT) as follows:
ΔT = Tf - Ti
ΔT = 21°C - 4°C = 17°C
### Energy Change:
It appears you have identified an energy change (ΔE), but you should ensure that this is consistent with the temperature change being calculated.
### Filling in the Blanks:
- **Blank 1 (Starting Temperature)**: **4°C** (this should reflect the initial temperature)
- **Blank 2 (Change in Temperature)**: **17°C** (this is the change you calculated)
- **Blank 3 (Ending Temperature)**: **21°C** (the final temperature after the change)
- **Blank 4**: **4 kJ/mol** (this is the energy change, assuming it's the energy change associated with the reaction)
### Question 2 - Endothermic or Exothermic?
- The reaction is **endothermic** (a). An endothermic reaction absorbs heat, which is consistent with a temperature decrease in the surroundings (like in a cold pack).
### Question 3 - Hot or Cold Pack?
- This reaction makes a **cold pack** (b). Since it's endothermic, it absorbs heat from its surroundings, making it feel cold.
### Summary:
- **Blank 1**: 4°C
- **Blank 2**: 17°C
- **Blank 3**: 21°C
- **Blank 4**: 4 kJ/mol
- **Question 2 Answer**: a (Endothermic)
- **Question 3 Answer**: b (Cold pack)
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