To determine which bowl can hold more water, we can calculate the volume of each bowl using the formula for the volume of a cylinder:
\[ V = \pi r^2 h \]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
For the first bowl:
- Height \( h_1 = 2 \)
- Radius \( r_1 = 2 \)
Calculating the volume:
\[ V_1 = \pi (2^2)(2) = \pi (4)(2) = 8\pi \]
For the second bowl:
- Height \( h_2 = 6 \)
- Radius \( r_2 = 1 \)
Calculating the volume:
\[ V_2 = \pi (1^2)(6) = \pi (1)(6) = 6\pi \]
Now we compare the volumes:
- Volume of the first bowl: \( 8\pi \)
- Volume of the second bowl: \( 6\pi \)
Since \( 8\pi > 6\pi \), the first bowl can hold more water.