Does(–5, –3)make the inequality 10x − 12y > –20true?

1 answer

To determine if the point \((-5, -3)\) satisfies the inequality \(10x - 12y > -20\), we can substitute \(x = -5\) and \(y = -3\) into the inequality.

First, substitute \(x\) and \(y\):

\[ 10(-5) - 12(-3) > -20 \]

Now calculate:

\[ -50 + 36 > -20 \]

Combining the terms on the left side:

\[ -50 + 36 = -14 \]

So the inequality becomes:

\[ -14 > -20 \]

Since \(-14\) is indeed greater than \(-20\), the point \((-5, -3)\) satisfies the inequality \(10x - 12y > -20\).

Therefore, the answer is yes, the inequality is true for the point \((-5, -3)\).