Does(2, 1)maketheinequality3x + 10y ≥ 20true?

Answer 1

To determine if the point (2, 1) makes the inequality \(3x + 10y \geq 20\) true, we can substitute \(x = 2\) and \(y = 1\) into the inequality.

1. Substitute \(x\) and \(y\):

\[ 3(2) + 10(1) \geq 20 \]

2. Calculate the left side:

\[ 6 + 10 = 16 \]

3. Now check the inequality:

\[ 16 \geq 20 \]

This statement is false because 16 is not greater than or equal to 20.

Thus, the point (2, 1) does not make the inequality \(3x + 10y \geq 20\) true.