To find the first, fourth, and tenth terms of the arithmetic sequence defined by the formula \( A(n) = -3 + (n - 1)(-2.2) \), we can substitute the values of \( n \) into the formula.
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First term (n = 1): \[ A(1) = -3 + (1 - 1)(-2.2) \] \[ A(1) = -3 + (0)(-2.2) \] \[ A(1) = -3 + 0 \] \[ A(1) = -3 \]
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Fourth term (n = 4): \[ A(4) = -3 + (4 - 1)(-2.2) \] \[ A(4) = -3 + (3)(-2.2) \] \[ A(4) = -3 - 6.6 \] \[ A(4) = -9.6 \]
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Tenth term (n = 10): \[ A(10) = -3 + (10 - 1)(-2.2) \] \[ A(10) = -3 + (9)(-2.2) \] \[ A(10) = -3 - 19.8 \] \[ A(10) = -22.8 \]
Thus, the first, fourth, and tenth terms of the arithmetic sequence are:
- First term: \(-3\)
- Fourth term: \(-9.6\)
- Tenth term: \(-22.8\)