Question

The triangle on the grid will be translated two units left.

On a coordinate plane, triangle A B C has points (negative 1, negative 1), (negative 1, negative 5), (0.5, negative 5).

Which shows the triangle when it is translated two units left?
On a coordinate plane, triangle A prime B prime C prime has points (1, negative 1), (1, negative 5), (2.5, negative 5).
On a coordinate plane, triangle A prime B prime C prime has points (negative 3, negative 1), (negative 3, negative 5), (negative 1.5, negative 5).
On a coordinate plane, triangle A prime B prime C prime has points (negative 1, 1), (negative 1, negative 3), (0.5, negative 3).
On a coordinate plane, triangle A prime B prime C prime has points (negative 1, negative 3), (negative 1, negative 7), (0.5, negative 7)

Answer 1

To translate the triangle two units left, you need to subtract 2 from the x-coordinates of each vertex of the triangle.

The original points of triangle ABC are:
- A: (-1, -1)
- B: (-1, -5)
- C: (0.5, -5)

Now, we will perform the translation by subtracting 2 from the x-coordinates:

1. For point A:
- New A = (-1 - 2, -1) = (-3, -1)

2. For point B:
- New B = (-1 - 2, -5) = (-3, -5)

3. For point C:
- New C = (0.5 - 2, -5) = (-1.5, -5)

After the translation, the new coordinates of triangle A'B'C' will be:
- A': (-3, -1)
- B': (-3, -5)
- C': (-1.5, -5)

Now, let's compare these new points to the options given:

1. Triangle A'B'C' has points (1, -1), (1, -5), (2.5, -5)
2. Triangle A'B'C' has points (-3, -1), (-3, -5), (-1.5, -5) (This one is correct)
3. Triangle A'B'C' has points (-1, 1), (-1, -3), (0.5, -3)
4. Triangle A'B'C' has points (-1, -3), (-1, -7), (0.5, -7)

Thus, the correct option that shows the triangle when it is translated two units left is the second one:
**On a coordinate plane, triangle A'B'C' has points (-3, -1), (-3, -5), (-1.5, -5).**